Saved Bookmarks
| 1. |
The photon energy in the frame K is equal to epsilon. Making use of the transformation formulas cited in the foregoing problem, find the energy epsilon^' of this photon in the frame K^' moving with a velocity V relative to the frame K in the photon's motion direction. At what value of V is the energy of the photon equal to epsilon^'=epsilon//2? |
|
Answer» Solution :For a PHOTON moving in the x direction `EPSILON=cp_x`, `p_y=p_z=0`, In the moving frame, `epsilon^'=(1)/(SQRT(1-beta^2))(epsilon-V(epsilon)/(c))=epsilonsqrt((1-V//c)/(1+V//c))` Note that `epsilon^'=epsilon/2` if, `1/4=(1-beta)/(1+beta)` or `beta=3/5`, `V=(3C)/(5)`. |
|