The pitentil energy of a satellite is given as `PE= lambda(KE)` where PE = potential energy of the satellite KE = kinetic energy of the satellite The vlaue of constant `lambda` isA. `-2`B. 2C. `-1//2`D. `+1//2`

The pitentil energy of a satellite is given as `PE= lambda(KE)` where

1.	The pitentil energy of a satellite is given as `PE= lambda(KE)` where PE = potential energy of the satellite KE = kinetic energy of the satellite The vlaue of constant `lambda` isA. `-2`B. 2C. `-1//2`D. `+1//2`
Answer» Correct Answer - A PE of satellite `=(GmM_(E))/(R_(E)+h)` `KE of satellite =1/2 (GmM_(E))/(R_(E)+h)` KE of satellite `=1/2 (GmM_(E))/(R_(E)+h)` `PE=-2 KE rarr lambda =-2`

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The pitentil energy of a satellite is given as `PE= lambda(KE)` where PE = potential energy of the satellite KE = kinetic energy of the satellite The vlaue of constant `lambda` isA. `-2`B. 2C. `-1//2`D. `+1//2`

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