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The plate current i_(p) in a triode valve is given i_(p)=K(V_(p)+mu V_(g))^(3//2) where i_(p) is in milliampere and V_(p) and V_(g) are in volt. If r_(p)=10^(4) ohm and g_(m)=5xx10^(-3)mho, then for i_(p)=8mA and V_(p)=300 volt, what of K and grid cur off voltage |
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Answer» `-6V,(30)^(3//2)` |
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