Saved Bookmarks
| 1. |
The plate current in a triode is given be I_p=0.004 (V_p+10V_g)^(3//2)mA where I_p,V_p and V_g are the values of plate current , plate voltage and grid voltage , respectively. What are the triode parameters mu,r_p and g_m for the operating point at V_p = 120volt and V_g =-2volt |
|
Answer» `10, 16.7 kOmega , 0.6 ` m mho `implies(DeltaI_p)/(DeltaV_g)=0.004[3/2(V_p+10V_g)^(1//2)xx10]xx10^(-3)` `implies g_m = 0.004 xx3/2(120+10xx-2)^(1//2)xx10xx10^(-3)` `implies g_m=6xx10^(-4)` mho = 0.6 mho Comparing the given equation of `I_p` with `I_p=K(V_p+muV_g)^(3//2)` we GET `mu=10` Also from `mu=r_pxxg_mimplies r_p=(mu)/(8_m)=10/(0.6xx10^(-3))` `implies r_p = 16.67 xx10^(3) Omega =16.67kOmega` |
|