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The plate voltage of a triode is increased from 225 V to 250 V, the grid voltage is changed from 4 to `-4.7V` to maintain plate current constant. The amplification factor of the tube isA. 35.7B. 2C. 70D. 20 |
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Answer» Correct Answer - A `V_(p_(1))=225V, V_(p_(2))=250V, V_(g_(1))=-4V` `V_(g_(2)) = -4.7V` `mu=((DeltaV_(p))/(DeltaV_(g)))_(l_(p))=(25)/(0.7) = 35.7` |
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