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The plates of a parallel plate capacitor have an area of100 cm^(2) each and are separated by 3 mm . The capacitor is charged by connecting it to a 400 V supply . Calculate the electrostatic energy stored in the capacitor . |
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Answer» Solution :Given ` A = 100 cm^(2) = 10^(2) xx 10^(-4) = 10^(-2) m^(2)` d = 3 MM = ` 3xx 10^(-3) m`, V = 400 V Electrical energy.E. `= 1/2 CV^(2) = (in _(0) AV^(2))/(2D) ` i.e., ` E = (8.854 xx 10^(-12) xx 10^(-2) xx (400)^(2))/(3 xx 10^(-3)) ` i.e., ` E = 2.361 xx 10^(-6) J` |
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