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The plates of a parallel plate capacitor have an area of 90 cm^2? each and are separated by 2.5 mm. The capacitor is charged by connecting it to a 400 V supply. How much electrostatic energy is stored by the capacitor ? |
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Answer» Solution :Here `A = 90 cm^2 = 90 XX 10^(-4) m^2, d = 2.5 mm = 2.5 xx 10^(-3) m and V = 400 V` `:." Capacitance " C = (epsi_0A)/d = (8.85 xx 10^(-12) xx 90 xx 10^(-4))/(2.5 xx 10^(-3)) = 31.86 xx 10^(-12) F` `:. " Electrostatic energy " U = 1/2 CV^2= 1/2 xx 31.86 xx 10^(-12) xx (400)^2 = 2.55 xx 10^(-6)J` |
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