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The platesof a parallelplate capacitorhave an area of 100 cm^2each and are separatedby 3mm.The capacitor is charged by connectingit to a 400 V supply. Calculate the electrostatic energy stored in the capacitor. |
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Answer» Solution :GIVEN `A=100 cm^2 =10^2 xx10^(-4)=10^(-2) m^2` , d=3 mm = `3XX10^(-3) ` m , V=400 V Electricalenergy `.E.=1/2CV^2=(epsilon_0AV^2)/(2d)` i.e., `E=(8.854xx10^(-12)xx10^(-2)xx(400)^2)/(3xx10^(-3))` i.e., `E=2.361xx10^(-6)` J |
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