Saved Bookmarks
| 1. |
The platesof a parallelplate capacitorhave an area of 100 cm^2each and are separatedby 3mm.The capacitor is charged by connectingit to a 400 V supply. if a dielectricis dielectricconstant2.5 isintroducedbetween the platesof the capacitor,then findthe electrostaticenergy storedand also change in theenergy stored. |
|
Answer» SOLUTION :`E^1=epsilon_r E=2.5xx2.361xx10^(-6)` `=5.903xx10^(-6)` J `DeltaE=E^1-E=(5.903-2.361)xx10^(-6)` J DIFFERENCE in theenergystored `DELTAF` , `DeltaE=3.542xx10^(-6)` J |
|