1.

The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by `x=6t and y=7t-5t^(2)`. What is the velocity of projection?A. `6ms^(-1)`B. `8ms^(-1)`C. `10ms^(-1)`D. `14ms^(-1)`

Answer» Correct Answer - c
`v_(x)=(dx)/(dt)=6 and v_(y)=(dy)/(dt)=8-10t`
`=8-10xx0=0`
`v=sqrt(v_(x)^(2)+v_(y)^(2))=sqrt(6(2)+8^(2))=10ms^(-1)`


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