The point of contact of the given circles x2+y2−6x−6y+10=0 and x2+ – InterviewSolution

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1.	The point of contact of the given circles x2+y2−6x−6y+10=0 and x2+y2=2, is
Answer» The point of contact of the given circles $x^{2} + y^{2} - 6 x - 6 y + 10 = 0$ and $x^{2} + y^{2} = 2$ , is

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