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The points (2, -2), (8, 4), (4, 6) and (-1, 1) in order are the vertices of which one of the following quadrilaterals ?A. SquareB. RhombusC. Rectangle (but not square)D. Trapezium

Answer» Correct Answer - D
Let points be A(2, -2), B(8, 4), C(4, 6) and D(-1, 1) in order and are vertices of a quadrilateral.
`AB^(2)=(8-2)^(2)+(4+2)^(2)=36+36=72`
`BC^(2)=(4-8)^(2)+(6-4)^(2)=16+4=20`
`CD^(2)=(4+1)^(2)+(6-1)^(2)=25+25=50`
`AD^(2)=(2+1)^(2)+(-2-1)^(2)=9+9=18`
Thus `AB ne BC ne CD ne AD`
Hence, quadrilateral is a trapezium.


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