InterviewSolution
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InterviewSolution
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The points (-4,0),(4,0) and (0,3) are the verticess of aA. right angled triangleB. isosceles triangleC. equilateral triangleD. scealene triangle |
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Answer» Correct Answer - b Let A(-4,0),B(4,0),C(0,3) are the given vertices. Now , distance between A(-4,0) and B(4,0), `AB=sqrt([4-(-4)]^(2)+(0-0)^(2))` [`:.` distance between two points `(x_(1),y_(1) and (x_(2),y_(2)) d=sqrt((x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2))]` `=sqrt((4+4)^(2))=sqrt(8^(2))=8` Distance between B(4,0) and C(0,3), and BC `=sqrt((0-4)^(2)+(3-0)^(2))=sqrt(16+9)=sqrt(25)=5` Distance between A(-4,0) and C(0,3), AC `=sqrt([0-(-4)]^(2)+(3-0)^(2))=sqrt(16+9)=sqrt(25)=5` `:.` BC =AC Hence , `triangleABC` is an isosceles triangle because an isosceles triangle has two sides equal. |
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