1.

The points A (3, 2, 1), B (5, 3, -2) and C (-1, 0, 7) are collinear.(a) True(b) FalseI had been asked this question in examination.The query is from Three Dimensional Geometry in division Three Dimensional Geometry of Mathematics – Class 11

Answer»

The correct option is (a) True

For EXPLANATION I would say: We know, distance between two points (x1, y1, z1) and (x2, y2, z2) is \(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}\).

Distance AB = \(\sqrt{(3-5)^2+(2-3)^2+(1+2)^2} = \sqrt{14}\)

Distance BC = \(\sqrt{(5+1)^2+(3-0)^2+(-2-7)^2} = 3\sqrt{14}\)

Distance AC = \(\sqrt{(3+1)^2+(2-0)^2+(1-7)^2} = 2\sqrt{14}\)

SINCE AB+AC = BC so, the three points are COLLINEAR.



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