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The points P(0, 6), Q(-5, 3) and R(3, 1) are the vertices of a triangle which isA. equilateralB. isoscelesC. scaleneD. right angled |
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Answer» Correct Answer - D `PQ^(2) = (-5-0)^(2) + (3-6)^(2) = (-5)^(2) + (-3)^(2) = 25 +9 = 34` `QR^(2) = (3+5)^(2) + (1-3)^(2) = 8^(2) + (-2)^(2) = 64+ 4 = 68` `PR^(2) = (3-0)^(2) + (1-6)^(2) = 3^(2) + (-5)^(2) = (9+25) = 34` `therefore PQ^(2) + PR^(2) = QR^(2)` Hence, `Delta PQR` is right-angled. |
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