1.

The polar form of - 3 is

Answer»

`(cospi+isinpi)`
`pm3(cospi+isinpi)`
`3(cospi+isinpi)`
`-3(cospi+isinpi)`

Solution :Let-3 = `R(COSTHETA +isintheta)`
`therefore""rcos theta=-3 and rsintheta=0`
Now, `r^(2)cos^(2)theta+r^(2)sin^(2)theta=(- 3)^(2)+0=9`
`RARR" "r^(2)(cos^(2)theta+sin^(2)theta)=9`
`rArr""r^(2)=9" "rArrr= 3`
Now, `{:("Now,",costheta=-1,,rArrtheta=pi),(and,sintheta=0 ,,rArr the ta= PIOR 2pi):}}rArr theta=pi`
Therefore, `-3=3(cospi+isinpi)`


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