The polynomial ky3+ 3y2– 3 and 2y3– 5y + k when divided by y – 4 – InterviewSolution

1.

The polynomial ky3+ 3y2– 3 and 2y3– 5y + k when divided by y – 4 leave the same remainder in eachcase. Find the value of k.

Answer»

Answer:

k =20

Step-by-step EXPLANATION:

y-4=0

y = 4

p(y)= -5y + k=0

p(4) = -5×4 +k=0

= -20+ k=0

k=20

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