the population of the town increase at the rate of 4% present populati

1.	the population of the town increase at the rate of 4% present population 60 to 500 what will be the population after 2 years
Answer» ong>ANSWER: The population of the town after 2 years is 562432. Step-by-step explanation: The exponential growth FUNCTION is defined as P=p_0(1+r)^tP=p 0 (1+r) t Where, p₀ is the INITIAL population, r is growth rate and is time in year. Initial population(p₀) = 500000 Growth rate(r) = 4% = 0.04 Time(in years)t = 2 P=500000(1+0.04)^3P=500000(1+0.04) 2 P=500000(1.04)^3P=500000(1.04) 2 P=562432

the population of the town increase at the rate of 4% present population 60 to 500 what will be the population after 2 years

Answer»

The population of the town after 2 years is 562432.

Step-by-step explanation:

The exponential growth FUNCTION is defined as

P=p_0(1+r)^tP=p

(1+r)

Where, p₀ is the INITIAL population, r is growth rate and is time in year.

Initial population(p₀) = 500000

Growth rate(r) = 4% = 0.04

Time(in years)t = 2

P=500000(1+0.04)^3P=500000(1+0.04)

P=500000(1.04)^3P=500000(1.04)

P=562432