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The position of a particle is given by r=3.0thati+2.0t^(2)hatj+5.0 hatk. Where t is in seconds and the coefficients hav the proper units for r to be in matres. (a) find v(t)and a(t) of the particle (b). Find the magnijtude of direction of v(t) or t=1.0 s |
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Answer» Solution :`V(t)(DR)/(dt)=(d)/(t)(30.t hati+2.0t^(2)hatj+5.0hatk)=3.0 hati+4.0.t hatj a(t)=(dv)/(dt)=+4.0 hatj` `a=4.0 m s^(-2)`along y directio (b)At `t=1.0s, v=3.0t hat i+4.0 hatj` It.s MAGNITUDE is `v=sqrt(3^(2)+4^(2))=5.0 m s^(-1)` and direction is `theta =TAN^(-1)((v_(y))/(v_(x)))= tan^(-1)((4)/(3))=53^(@)` with x-axis. |
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