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The position vector of a particle is `vec( r) = a cos omega t i + a sin omega t j`, the velocity of the particle isA. parallel to the position vectorB. perpendicular to the position vectorC. directed towards the originD. directed away from the origin |
Answer» Correct Answer - B `vec( r) = a cos theta omega t hat (i) + alpha sin omega t hat(j)` `vec(v ) = ( dvec(r ))/(dt) = -a sin omega t + a cos omega t . omega hat(j)` `vec( r) . vec(v ) = 0 , vec(r )` and `vec(v) are_|_^(ar)`. |
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