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The position `x` of a particle varies with time `t` as `x=at^(2)-bt^(3)`. The acceleration at time `t` of the particle will be equal to zero, where (t) is equal to .`A. `alpha/beta`B. `(2alpha)/(3beta)`C. `alpha/(3beta)`D. zero |
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Answer» Correct Answer - C `x=alphat^(2)-betat^(3)` `v=(dx)/(dt)=2alphat-3betat^(2)` `a=(dv)/(dt)=2alpha-6betat` `a=0=2alpha-6betatimpliest=alpha/(3beta)` |
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