1.

The potential difference applied to an X-ray tube is 5 kV and the current through it is 3.2 mA. The number of electrons stricking the target per second is ......(Take e=1.6xx10^(-19)C)

Answer»

`4xx10^(16)`
`2XX10^(16)`
`1.6xx10^(16)`
`2xx10^(-6)`

Solution :`I=(Q)/(t)=("ne")/(t)`
`:. n=(It)/(e)=(3.2xx10^(-3)xx1)/(1.6xx10^(-19))`
`:.n=2xx10^(16)`


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