1.

The potential difference applied to an X-ray tube is 5kV and the current through it is 3.2 mA. Then the number of electrons striking the target per second is

Answer»

` 2 XX 10^(16)`
`5 xx 10^(18)`
`1 xx 10^(17)`
`4 xx 10^(5)`

Solution :`N = (It)/(e) = (3.2 xx 10^(-3)xx1)/(1.6 xx 10^(-19)) = 2 xx 10^(16)`


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