1.

The potential difference applied to an X-ray tube is 5 kV and the current through it is3.2 mA. The number of electrons striking the target per second is

Answer»

`5 xx 10^16`
`2 xx 10^16`
`1 xx 10^17`
`4 xx 10^15`

Solution :NUMBER of electrons striking the target of X-ray tube per second is
`n= I/e = (3.2 mA)/(1.6 xx 10^(-19) C) = (3.2 xx 10^(-3 )A)/(1.6 xx 10^(-19) C) = 2 xx 10^16 s^(-1)`


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