InterviewSolution
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InterviewSolution
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The potential difference applied to an X-ray tube is 5k V and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is. (a) `2xx10^16` (b) `5xx10^6` (c ) `1xx10^17` (d) `4xx10^15`.A. `2 xx 10^(16)`B. `5 xx 10^(16)`C. `1 xx 10^(17)`D. `4 xx 10^(15)` |
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Answer» Correct Answer - A `i = (Ne)/(t) rArr (N)/(t) = (i)/( e) = (3.2 xx 10^(-3))/(1.6 xx 10^(-19)) = 2 xx 10^(16)//sec` |
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