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The potential difference applied to an X-ray tube is 5k V and the current through it is 3.2 mA. Then, the number of electrons striking the target per second is. (a) `2xx10^16` (b) `5xx10^6` (c ) `1xx10^17` (d) `4xx10^15`.A. `2 xx 10^(14)`B. `5 xx 10^(6)`C. `1 xx 10^(12)`D. `4 xx 10^(15)` |
Answer» Correct Answer - A `i=q/t=(n e)/t implies n= (I t)/e` Substituting `=3.2xx10^(-3) A` `e=1.6xx10^(-19) C` and `t=1 s` We get, `n=2xx10^(16)` |
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