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The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface , having work function `5.01 eV` , when ultraviolet light of `200 nm` falls on it , must beA. 2.4 VB. – 1.2 VC. ) – 2.4 VD. 1.2 V |
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Answer» Correct Answer - B `hv=phi_(0)+eV_(0)` where `hv=(12400)/(2000)=6.2eV` `implies V_(0)=6.2-5.01=1.19~~1.20V` |
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