The potential differences `V` and the current `i` flowing through an instrument in an `AC` circuit of frequency `f` are given by `V=5 cos omega t` and `I=2 sin omega t` amperes (where `omega=2 pi f`). The power dissipated in the instrument isA. zeroB. `10W`C. `5W`D. `2.5 W`

The potential differences `V` and the current `i` flowing through an i

1.	The potential differences `V` and the current `i` flowing through an instrument in an `AC` circuit of frequency `f` are given by `V=5 cos omega t` and `I=2 sin omega t` amperes (where `omega=2 pi f`). The power dissipated in the instrument isA. zeroB. `10W`C. `5W`D. `2.5 W`
Answer» Correct Answer - A `V=5 cos omega t=5sin(omega t+(pi)/2)` and `i=2 sin omegat` Power `=V_(rms)xxi_(rms)xxcos varphi=0` (Since `varphi=(pi)/2`, therefore `cos varphi=cos((pi)/2)=0`)

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The potential differences `V` and the current `i` flowing through an instrument in an `AC` circuit of frequency `f` are given by `V=5 cos omega t` and `I=2 sin omega t` amperes (where `omega=2 pi f`). The power dissipated in the instrument isA. zeroB. `10W`C. `5W`D. `2.5 W`

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