The potential different across the Coolidge tube is `20 kV and 10 m A` current flows through the voltage supply. Only `0.5%` of the energy carried by the electrons striking the largest is converted into X-ray. The power carried by the X-ray beam is `p`. ThenA. `0.1`B. `1W`C. `2W`D. `10W`

The potential different across the Coolidge tube is `20 kV and 10 m A`

1.	The potential different across the Coolidge tube is `20 kV and 10 m A` current flows through the voltage supply. Only `0.5%` of the energy carried by the electrons striking the largest is converted into X-ray. The power carried by the X-ray beam is `p`. ThenA. `0.1`B. `1W`C. `2W`D. `10W`
Answer» Correct Answer - B power drawn by coolidge tube =`20xx10^(3)xx10xx10^(-3)=200W` Power of x-rays =`(0.5)/(100)xx200=1W`

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The potential different across the Coolidge tube is `20 kV and 10 m A` current flows through the voltage supply. Only `0.5%` of the energy carried by the electrons striking the largest is converted into X-ray. The power carried by the X-ray beam is `p`. ThenA. `0.1`B. `1W`C. `2W`D. `10W`

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