InterviewSolution
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InterviewSolution
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The potential energy function for a particle executing linear SHM is given by `V(x)= 1/2kx^2` where k is the force constant of the oscillator. For `k = 0.5 Nm^(-1)`, the graph of V(x) versus x is shown in the figure A particle of total energy E turns back when it reaches `x=pmx_m`.if V and K indicate the potential energy and kinetic energy respectively of the particle at `x= +x_m`,then which of the following is correct? A. V=O,K=EB. V=E,K=OC. V lt E, K=OD. V=O, K lt E |
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Answer» Correct Answer - B (b) Total energy is `E=PE+KE " "……….(i)` When particle is at `x=x_(m)` i.e., at extreme position, returns back. Hence, at `x=x_(m)`,x=0,KE=0 `E=PE+0=PE=V(x_(m))=(1)/(2)kx_(m)^(2)` |
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