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The potential energy of a force filed `vec(F)` is given by `U(x,y)=sin(x+y)`. The force acting on the particle of mass m at `(0,(pi)/4)` isA. 1B. `sqrt(2)`C. `1/(sqrt(2))`D. 0 |
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Answer» Correct Answer - A `(delU)/(dely)=cos(x+y).` `(delU)/(dely)=cos(x+y)` `vec(F)=-cos(x+y)hati-cos(x+y)hatj` `=-cos(0+(pi)/4)hati-cos(0+(pi)/4)hatj` `|vec(F)|=1` |
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