1.

The potential energy of a particle executing S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle will be

Answer» PE`=(1)/(2)kx^(2)implies(1)/(2)k(A^(2))/(4)=2.5 " "(because x=(A)/(2))`
where , x is the displacement of the particle and A is the amplitude.
`implies` Total energy `=(1)/(2)kA^(2)=2.5xx4=10 J`


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