1.

The potential energy of a particle in a conservative field is U = frac{a}{r^3}-frac{b}{r^2} , where a and b are positive constants and r is the distance of particle from the centre of field. For equilibrium, the value of r is

Answer»

`FRAC{2A}{b}`
`frac{3a}{2B}`
`frac{a}{2b}`
`frac{a}{b}`

ANSWER :b


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