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The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9 J and its amplitude is 0.01 m, its time period would beA. `(pi)/(10)s`B. `(pi)/(20)`sC. `(pi)/(50)s`D. `(pi)/(100)s` |
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Answer» Correct Answer - D `(1)/(2)mv_(max)^2=9-5=4` or `mv_(max)^2=8` or `2v_(max)^2=8` or `v_(max)=2(m)/(s)=Aomega` `omega=(v_(max))/(A)=(2)/(0.01)=200` or `(2pi)/(T)=200` `T=(2pi)/(200)=(pi)/(100)` |
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