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The potential energy of particle moving is S.H.M. is (1)/(2)kx^(2). If the frequency of the particle is n, the frequency of oscillation of P.E. is : |
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Answer» Solution :Here `x=r SIN omegat`. and P.E. `=(1)/(2)kx^(2)=(1)/(2)m omega^(2)x""{because k=m omega^(2)}` P.E. `=(1)/(2)m omega^(2).r^(2)sin^(2)omegat` P.E. `=(1)/(2)m omega^(2)r^(2)[(1-cos 2omegat)/(2)]` `:.` THEREFORE, frequency of P.E. is `2omega` i.e., TWICE the frequency of particle `(omega)`. Hence correct choice is (b). |
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