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The potential energy of the orbital electron i the ground state of hydrogen atom is -E. What is its kinetic energy? |
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Answer» `(E)/(4)` `(MV^(2))/(r)=(KE^(2))/(r^(2)) RARR (1)/(2) mv^(2)=(ke^(2))/(2r)...(1)` Potential energy `=-(ke^(2))/(r)....(2)` Say E is potential energy then `E=-(ke^(2))/(r)` `:.` Kinetic energy `=-(ke^(2))/(r)=(1)/(2)(-(ke^(2))/(r))` `:.`Kinetic energy `=(E)/(2)` |
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