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The potential enery of a charged parallel plate capacitor is `U_(0)`. If a slab of dielectric constant K is inserted between the plates, then the new potential energy will beA. `(U_(0))/(k)`B. `U_(0)k^(2)`C. `(U_(0))/(k^(2))`D. `U_(0)^(2)` |
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Answer» Correct Answer - A |
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