1.

The potential of the cell for the reaction M(s)+2H^(+)(1M)toH_(2)(g)(1atm)+M^(2+)(0.1M) is 1.500 V. the standard reduction potential for M^(2+)//M(s) couple is

Answer»

`0.1470V`
`1.470V`
`1.47V`
none of these

Solution :The cell is `M|M^(2+)(0.1M)||H^(+)(1M)|H_(2)(1atm)`
`E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"[M^(2+)]`
`therefore1.50=E_(cell)^(@)-(0.0591)/(2)xxlog(0.1)`
`=E_(cell)^(@)+0.02955`
or `E_(cell)^(@)=1.50-0.02955=1.47045V`
But `E_(cell)^(@)=E_(H^(+)//(1)/(2)H_(2))^(@)-E_(M^(2+)//M)^(@)`
i.e., `1.47=0-E_(M^(2+)//M)^(@)`
or `E_(MG^(2+)//M)^(@)=-1.47M`


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