The power of a wave of with voltage of 140V and a characteristic impedance of 50 ohm is(a) 1.96(b) 19.6(c) 196(d) 19600The question was asked in an online interview.My doubt is from Power, Power Loss and Return Loss topic in chapter EM Wave Propagation of Electromagnetic Theory

The power of a wave of with voltage of 140V and a characteristic imped

1.	The power of a wave of with voltage of 140V and a characteristic impedance of 50 ohm is(a) 1.96(b) 19.6(c) 196(d) 19600The question was asked in an online interview.My doubt is from Power, Power Loss and Return Loss topic in chapter EM Wave Propagation of Electromagnetic Theory
Answer» The correct answer is (C) 196 Best EXPLANATION: The power of a wave is given by P = V^2/2Zo, where V is the generator VOLTAGE and ZO is the characteristic impedance. on substituting the given data, we get P = 140^2/(2×50) = 196 units.

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The power of a wave of with voltage of 140V and a characteristic impedance of 50 ohm is(a) 1.96(b) 19.6(c) 196(d) 19600The question was asked in an online interview.My doubt is from Power, Power Loss and Return Loss topic in chapter EM Wave Propagation of Electromagnetic Theory

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