1.

The power of pump, which can pump 200 kg of water to height of 200 m in 10 s `(g=10(m)//(s^2)`)A. 40 kWB. 80 kWC. 400 kWD. 960 kW

Answer» Correct Answer - A
`overlineP=(mgh)/(t)=((200)(10)(200))/(3600)=40000W`
`=40kW`


Discussion

No Comment Found

Related InterviewSolutions