1.

The power output for a certain laswer transition was found to be 2.79 watt per square meter. Givne lambda = 520nm, calculate the number of quanta emitted per square meter per second.

Answer»

Solution :Energy corresponding to the photon `= ( 6.626 xx 10^(-34) xx 3 xx 10^(8))/( 520 xx 10^(-9))`
`= 3.822 xx 10^(-19) J `
the power output `= 2.79 ` Watt `//m^(2)`
`= 2.79 J // `SEC `//m^(2)`
`:.`no. of photons EMITTED per sq. METER sec`= ( 2.79 )/( 3.822 xx 10^(-18)) = 7.20 xx 10^(18)`


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