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The power radiated by a black is `P` and it radiates maximum energy around the wavelength `lambda_(0)` If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength `3lambda_(0)//4` the power radiated by it will increase by a factor of .A. `4//3`B. `16//9`C. `64//27`D. `256//81` |
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Answer» Correct Answer - D `P=sigmaAT^(4)` and `lambda_(m)T=const(P_(2))/(P_(1))=((T_(2))/(T_(1)))^(4)` |
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