The present ages of A and B are in the ratio 7 : 5. Ten years later, t

1.	The present ages of A and B are in the ratio 7 : 5. Ten years later, their ages will be in the ratio 9:7. Find their present ages. @PLEASE HELP@
Answer» Answer: LET A be Leena and B be Heena. So, Let the RATIONAL between ages of Leena and Heena be x. The ages of Leena and Heena are in the ratio 7:5. Thus there ages are, Leena 7X and Heena 5x Ten years hence, the ratio of their ages will be 9:7. 10 year hence their ages will be: Leena’s age 7x + 10 Heena’s age 5x + 10 The ratio of their ages 7x + 10 / 5x + 10 = 9 / 7 Cross multiplication: 9 ( 5x + 10 ) = 7 ( 7x + 10 ) 45x + 90 = 49x + 70 45x - 49x = 70 - 90 —5x = -20 5x = 20 x = 20/5 x = 4 The rational is 4 Their respective ages are, Leena’s age 7x = 7 × 4 = 28 years Heena’s age 5x = 5 × 4 = 20 years •°• Leena’s age is 28 years and Heena’s age is 20 years. Hope this helps you!!. Mark me as brainliest.

The present ages of A and B are in the ratio 7 : 5. Ten years later, their ages will be in the ratio 9:7. Find their present ages. @PLEASE HELP@

Answer»

Answer:

LET A be Leena and B be Heena.

So,

Let the RATIONAL between ages of Leena and Heena be x.

The ages of Leena and Heena are in the ratio 7:5.

Thus there ages are, Leena 7X and Heena 5x

Ten years hence, the ratio of their ages will be 9:7.

10 year hence their ages will be:

Leena’s age 7x + 10

Heena’s age 5x + 10

The ratio of their ages

7x + 10 / 5x + 10 = 9 / 7

Cross multiplication:

9 ( 5x + 10 ) = 7 ( 7x + 10 )

45x + 90 = 49x + 70

45x - 49x = 70 - 90

—5x = -20

5x = 20

x = 20/5

x = 4

The rational is 4

Their respective ages are,

Leena’s age 7x = 7 × 4 = 28 years

Heena’s age 5x = 5 × 4 = 20 years

•°• Leena’s age is 28 years and Heena’s age is 20 years.