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The present ages of Rafi and fathima are in the ratio 7:5. Ten years later the ratio of their ages will be 9:7. find their present ages. |
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Answer» n :Since the presen ratios of ages of Rafi and Fathima is 7:5,We MAY take, Rafi's age to be 7x and the Fathima's age to be 5x(NOTE that ratio of 7x and 5x is 7x: 5x and which is same as 7:5)After 10 years Rafî's age = 7x + 10and Fathima's age = 5x + 10After 10 years, the ratio of Rafi's age and Fathima's age is 7x + 10 : 5x + 100But according to the given DATA this ratio is EQUAL to 9 : 77x + 10 : 5x + 10 = 9 : 7ie., 7 (7x + 10) = 9 (5x + 10)49 x+ 70 =45 x+90.The above equation is 49x + 70 =45X + 9049x - 45x = 90 - 70 (Transposing 70 to RHS and 45x to LHS)4x= 20 x = 20/4=> x = 5=> Raff's age = 7x = 7 x 5 = 35 years Fathima's age = 5x = 5 x 5 = 25 years |
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