1.

The pressure and temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would beA. `2 dm^(3)`B. `3 dm^(3)`C. `4 dm^(3)`D. `8 dm^(3)`

Answer» Correct Answer - C
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)), (P_(1)xx4)/(T_(1))=(2P_(1)xxV_(2))/(2T_(1))`
`8 = 2 xx V_(2)` so `V_(2)= 4 dm^(3)`


Discussion

No Comment Found

Related InterviewSolutions