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The pressure exerted by an ideal gas is `P = (1)/(3) (M)/(V)C^(2)`, where the symbols have their usual meaning. Using standard gas equation, PV = RT, we find that `C^(2) = (3 RT)/(M) or C^(2) oo T`. Average kinetic energy of translation of one mole of gas ` =(1)/(2) MC^(2) = (3 RT)/(2)` with the help of the passage given above, choose the most appropriate alternative for each of the following quetions : Average thermal energy of a helium atom at 600 K would beA. `6.21 xx 10^(-21) J`B. `1.24 xx 10^(-20) J`C. `1.24 xx 10^(-21) J`D. `1.24 xx 10^(21) J` |
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Answer» Correct Answer - B When `T = 600K` thermal energy//atom = `3/2 kT` `=3/2 xx (1.38 xx 10^(-23)) xx 600 = 1.24 xx 10^(-20)J`. |
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