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The pressure inside a small air bubble of radius `0.1`mm situated just below the surface of water will be equal to [Take surface tension of water `70xx10^-3Nm^-1` and atmospheric pressure`=1.013xx10^5Nm^-2`]A. `2.954xx10^3Pa`B. `1.027xx10^3Pa`C. `1.027xx10^5Pa`D. `2.054xx10^5Pa` |
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Answer» Correct Answer - C Excess pressure inside the air bubble`=(2T)/(r )` `impliesP_(in)-P_(out)=(2T)/(r )=(2xx70xx10^-3)/(0.1xx10^-3)=1400Pa` `impliesP_(in)=1400+1.013xx10^5` `=0.014xx10^5+1.013xx10^5=1.027xx10^5Pa` |
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