The pressure of a gas at -173°C temperature is 1 molecules is increas

1.	The pressure of a gas at -173°C temperature is 1 molecules is increased to 2N, what will be the effect on the pressure of the gas? On the total energy of the gas? On the root-mean-square speed of the molecules?
Answer» Since ∝ = 1/3 mn/v c², i.e., p∝ n, therefore, pressure will be doubled when number of molecules n becomes 2n. As kinetic energy of the gas = 1/2 x mn c², therefore K.E. of the gas also becomes double when n changes to 2n. Since, r.m.s. velocity of molecules of a gas only depends upon the temperature, hence r.m.s. velocity of the molecules will remain the same when n changes to 2n. When p becomes double, then temperature becomes double. As C ∝ √T, therefore r.m.s velocity becomes √2 C.

The pressure of a gas at -173°C temperature is 1 molecules is increased to 2N, what will be the effect on the pressure of the gas? On the total energy of the gas? On the root-mean-square speed of the molecules?

Answer»

Since ∝ = 1/3 mn/v c², i.e., p∝ n, therefore, pressure will be doubled when number of molecules n becomes 2n. As kinetic energy of the gas = 1/2 x mn c², therefore K.E. of the gas also becomes double when n changes to 2n. Since, r.m.s. velocity of molecules of a gas only depends upon the temperature, hence r.m.s. velocity of the molecules will remain the same when n changes to 2n.

When p becomes double, then temperature becomes double. As C ∝ √T, therefore r.m.s velocity becomes √2 C.

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The pressure of a gas at -173°C temperature is 1 molecules is increased to 2N, what will be the effect on the pressure of the gas? On the total energy of the gas? On the root-mean-square speed of the molecules?

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