1.

The pressure of an ideal gas undergoin isothermal change is increased by 10%. The volume of the gas must decrease by about

Answer»

<P>`0.1%`
`9%`
`10%`
`0.9%`

Solution :Giventhat `DELTAP =(10)/(100)xx p= 0.1p`
Now `(p+Deltap) =11p`
From `Delta v = ((v-v)/(v)) xx 100`
`=(1-(10)/(11))xx 100 =9%`


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