The price of mustard oil is increased by 10%. Due to which a family re

1.	The price of mustard oil is increased by 10%. Due to which a family reduces its consumption so that the increment in the expenditure on mustard oil is increased by 5%. If consumption of mustard oil is 12 kg before the increment. Find the new consumption.1. \(11\frac{5}{{11}}\;kg\)2. \(12\frac{5}{{11}}\;kg\)3. \(13\frac{5}{{11}}\;kg\)4. \(14\frac{5}{{11}}\;kg\)5. \(15\frac{5}{{11}}\;kg\)
Answer» Correct Answer - Option 1 : \(11\frac{5}{{11}}\;kg\) Given: Initial consumption of mustard oil = 12 kg Percentage increase in the price of mustard oil = 10% Percentage increment in price = 5% Formula used: Expenditure = Price × Consumption Calculation: Let the initial price of mustard oil be x Expenditure on mustard oil = 12x ⇒ After increment expenditure on mustard oil = (105/100) × 12x = (63/5)x ⇒ Price of mustard oil = (110/100) × x = (11/10)x ⇒ Consumption after increment = {(63/5)x}/{(11/10)x} ⇒ Consumption after increment = {(63 × 10)/(5 × 11)} = 126/11 = \(11\frac{5}{{11}}\;kg\) ∴ The new consumption is \(11\frac{5}{{11}}\;kg\)

The price of mustard oil is increased by 10%. Due to which a family reduces its consumption so that the increment in the expenditure on mustard oil is increased by 5%. If consumption of mustard oil is 12 kg before the increment. Find the new consumption.1. \(11\frac{5}{{11}}\;kg\)2. \(12\frac{5}{{11}}\;kg\)3. \(13\frac{5}{{11}}\;kg\)4. \(14\frac{5}{{11}}\;kg\)5. \(15\frac{5}{{11}}\;kg\)

Answer» Correct Answer - Option 1 : \(11\frac{5}{{11}}\;kg\)

Given:

Initial consumption of mustard oil = 12 kg

Percentage increase in the price of mustard oil = 10%

Percentage increment in price = 5%

Formula used:

Expenditure = Price × Consumption

Calculation:

Let the initial price of mustard oil be x

Expenditure on mustard oil = 12x

⇒ After increment expenditure on mustard oil = (105/100) × 12x = (63/5)x

⇒ Price of mustard oil = (110/100) × x = (11/10)x

⇒ Consumption after increment = {(63/5)x}/{(11/10)x}

⇒ Consumption after increment = {(63 × 10)/(5 × 11)} = 126/11 = \(11\frac{5}{{11}}\;kg\)

∴ The new consumption is \(11\frac{5}{{11}}\;kg\)